6 replies to this topic

[JinR]

Hey guys, which level ring should I get?  I know 15* is way too expensive.  I wanted to aim for an 8*-10*.  Will this take long and what do I do? I never attempted to get these rings so I dont know the process..

 

Can someone give me a short guide on what to do to make an 8*-10* solar ring?

 

 

 

 

[StormHaven]

http://ds.irowiki.or...F6_Defense_Mode

 

this will explain the ring system and how to make them.

[JinR]

Err I get confused with the reinforcing thing.  I know that it takes 420 3* rings to make a 15*. 

 

So how many 3* rings will it take to make an 8*, 9*, 10*? Sorry I'm slow, haha..

 

[StormHaven]

I'm horrendous with math so....someone else jump in here.

[Coolsam]

Err I get confused with the reinforcing thing.  I know that it takes 420 3* rings to make a 15*. 

 

So how many 3* rings will it take to make an 8*, 9*, 10*? Sorry I'm slow, haha..

 

Typically the most affordable with best bonuses would be 10-star.

 

So.... at 3 3*s = 2 4*s. Take a number of 3* rings, get as close to that number without going over and divide it by 3. Make sure you have a result w/ no decimals. Then multiply it by 2. That determines how many of the next ring that gives. So 24 3*'s / 3 = 8 x 2 = 16 4*'s.

 

24 3*'s = 16 4*'s = 10 5*'s = 6 6*'s = 4 7*s = 2 8*'s

You'll have 1 4*, 1 5*, and 1 7* as well.

 

So 24 3* rings will get you 2 8* rings.

 

Meaning to get the 3rd 8* ring to make 2 9*'s we'd have to get the 8*'s again. But using your leftover rings, you can work to it alittle easier.

3 3*'s = 2 4*+ 1 4* = 3 4* = 2 5* + 1 5*  = 2 6* + 1 7*

Now work your way to 2 more 6*s

12 3*'s = 8 4*'s = 4 5*'s = 2 6* + 2 6* = 4 6* = 2 7* + 1 7* = 2 8*

With your other 2 8*'s, you'll have:

2 9-stars + 1 8-star + 1 6-star + 1 5-star + 2 4-stars.

 

And it takes a total for 39 3* rings for 9* Caracha solars. And if you continue to save left-over rings, it slightly reduces the 3*'s needed to work to 10*.

Let's try 15 3*'s to work for that 3rd 9* ring for 10*'s.

15 3*'s = 10 4*s + 2 4* leftovers = 12 4*s = 8 5*'s + 1 5* leftover = 9 5*'s = 6 6*'s = 4 7*s = 2 8*s + 1 8* leftover = 3 8*s = 2 9*s + 2 9*s = 4 9*s = 2 10*'s

 

So..... 39 rings for 9*s, add in 15 more 3*'s w/ the leftovers.....

 

It takes 54 3* ancient caracha rings to make 2 10*s with..... 1 9* and  1 7* leftover.

 

And for solars, that's upto 25 hunches a F6 per 3* ring. Assuming you do hunches every stage which is 1+(3xStages done after first hunch use in a row) so 1+(3x8)=25

54x25=1350 Perfect Hunches

 

However, with Star Fragments. You can trade 2 1*'s into 1 2* ring. And 2 2* rings into 1 3* ring.

 

So if you were to save 1-2* solar rings and trade em all in for 3*'s, you'd potentially save a bit on hunches.

 

I'm not gonna go too much into how much it costs for a set of 15* solars.

 

Hope this helps, my math may be sloppy.

[JinR]

.___. I didn't know it was this complicated seesh.  Sorry CoolSam for making you write that out haha but it was VERY helpful.  Hmm...

 

 

So like, $67 ish for 1350 perfect hunches. HMM.. To f6 or not to f6..

 

[SalvadorCirinsa]

This helps CoolSam! ~ simple and clear!